Question

8. As a roller coaster car crosses the top of a 51.0-m-diameter loop-the-loop, it's apparent weight is 1.80 times its true weight. What is the car's speed at the top? (The apparent weight is the same as the force of the tracks on the car)

Answer 1

The velocity at the top will be 26.4522 m/sec

Step-by-step explanation:

We have given

The diameter of the loop d = 48.01 m

Radius of the loop
`r=(d)/(2)=(51)/(2)=25.5m`

The apparent weight at the top is given by
`(mv^2)/(r)-mg`

As the in question it is given that apparent weight is equal to 1.80 times of the real weight

`(mv^2)/(r)-mg=1.8mg`

`(mv^2)/(r)=2.8mg`

`v=√(2.8rg)=√(2.8* 25.5* 9.8)=26.4522m/sec`

So the velocity at the top will be 26.4522 m/sec