Question

Write an equation in slope-intercept form for the line that passes through (-4,6) and its perpendicular to the graph of 2x+ 3y =12

Answer 1

y = 3/2x

Explanation:

1.) the slope of 2x+3y=12 is -2/3 so take opposite and get 3/2.

2.) then use point slope form: y-6=3/2(x-4)

3.) distribute: y-6=3/2x-6

4.) put in point slope and get: y=3/2x (cause -6+6=0)