Question

Two straight wires carry current of 5A opposite direction separated by a distance of 30cm. What is the magnitude of magnetic field at point P exactly the middle of them 15cm from each wire

Answer 1

The magnitude of magnetic field of both wires is β= 13. 33
`x10^(-6)`T

Step-by-step explanation:

`p=15cm*(1m)/(100cm)=0.15m`

`I=5A`

`u_(o) = 4*\pi x10^(-7)`

Using the right hand rule field magnetic as the current go in opposite direction the field in the point exactly in the middle have the same direction both so

`\beta _(t) =\beta _(1)+\beta _(2)`

They have the same direction and the P point is the middle as the same current field can be find:

`\beta _(t) =\beta _(1)*2`

`\beta = (u_(o)*I )/(2*\pi *p) \\\beta =(4*\pi x10^(-7)*5A )/(2*\pi *(30)/(2) ) \\\beta =(4x10^(-7)*5 )/(0.30) \\\beta =6.6x10^(-6)`T

`\beta _(t) =6.6x10^(-6)*2`=13.33
`x10^(-6)`T