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Solve the formula A=1/2h(a+b) for a

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\bf A=\cfrac{1}{2}h(a+b)\implies A=\cfrac{h(a+b)}{2}\implies 2A=h(a+b) \\\\\\ \cfrac{2A}{h}=a+b\implies \cfrac{2A}{h}-b=a

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User Kylie
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