Given that ABCD is a rhombus, what is the value of x?

Question

asked Apr 28, 2020 101k views

2 Answers

MrMesees · Answer 1 · 2020-05-04T18:04:57+0000

Answer:

x is 29

Explanation:

In a rhombus diagonals bisect perpendicularly.

let the centre point of the rhombus be O.

By seeing the diagram we can say that Angle DBC is congruent to angle ADB.

We can say they are congruent because they are symmetric about the diagonals and also by the principle of parallel lines.

Also ADB is a right angled triangle so ,

x+(3x-26)=90

$4x=116\\ x=29$

Hence the value of x is 29.