Question

Please help quick.

What is the equation of the quadratic graph with a focus of (5, −1) and a directrix of y = 1?


f(x) = − one fourth (x − 5)2 + 1

f(x) = one fourth (x − 5)2 + 1

f(x) = − one fourth (x − 5)2

f(x) = one fourth (x − 5)2

Answer 1

The answer to your question is: third option is correct

Explanation:

Data

F (5, -1)

directrix y = 1

Then, after getting the graph, the vertix = (5, 0)

and p = 1

Formula

(x - h) ² = -4p(y - k)

(x - 5)² = -4(1)(y - 0)

(x - 5)² = -4y

y = (x - 5)² / -4