Question

Durante un intento juego de croquet, una bola de 0.52 kg en reposo sobre el cesped es golpeada por un mazo con una fuerza promedio de 190 n, si el mazo esta en contacto con la bola durante 7.2 x 10^-3 s, cual es la rapidez de la bola justo despues de ser golpeada?

Answer 1

Answer: 2.63 m/s

Step-by-step explanation:

The question in english is written below:

During an attemp of croquet game, a 0.52 kg ball at rest on the grass is hit by a mallet with an average force of 190 N, if the mallet is in contact with the ball for
`7.2(10)^(-3) s`, Whay is the speed of the ball just after being hit?

According to Newton's second law of motion, the force
`F` exerted on an object is directly proportional to its mass
`m` and acceleration
`a`:

`F=m.a` (1)

On the other hand, acceleration is defined as the variation of velocity
`V` in time
`t`:

`a=(V)/(t)` (2)

Substituting (2) in (1):

`F=m(V)/(t)` (3)

Where:

`F=190 N`

`m=0.52 kg`

`t=7.2(10)^(-3) s`

Isolating the velocity
`V` from (3):

`V=(Ft)/(m)` (4)

`V=((190 N)(7.2(10)^(-3) s))/(0.52 kg)`

Finally:

`V=2.63 m/s`