asked 37.4k views
1 vote
HELP DUE IN AN HOUR

Solve for x.

4(x+1)≤4x+3




A x≤7

B all real numbers

C x≤1

D no solution

asked
User Nauti
by
8.1k points

2 Answers

5 votes

Answer:

no solution. not 100% sure though

HELP DUE IN AN HOUR Solve for x. 4(x+1)≤4x+3 A x≤7 B all real numbers C x≤1 D no solution-example-1
answered
User Xaser
by
8.4k points
0 votes

Answer:

D) no solution.

Explanation:

4(x + 1) ≤ 4x + 3

First, distribute 4 to all terms within the parenthesis:

4(x + 1) = 4(x) + 4(1) = 4x + 4

4x + 4 ≤ 4x + 3

Isolate the variable, x. Treat the "≤" as an equal sign, what you do to one side, you do to the other. Subtract 4x and 4 from both sides:

4x (-4x) + 4 (-4) ≤ 4x (-4x) + 3 (-4)

4x - 4x ≤ 3 - 4

0 ≤ -1

Since x was eliminated from the inequality, and you need the x for the inequality, your answer is D) no solution.

~

answered
User Ding
by
7.7k points

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