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10 votes
Can someone please prove that the expression (x-y)+(y-z)+(z-x) is equivalent to 0

1 Answer

11 votes

Answer:

see below

Explanation:


(x-y)+(y-z)+(z-x)\\\\=x-y+y-z+z-x\\\\=(x-x)+(-y+y)+(-z+z)\\\\=0+0+0\\\\=0

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User Blessy
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