Mrs. Rouse has three times as many gladiolus as Mrs. Leal together they have 128 gladiolus write the system of equations for this situation ?

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asked Apr 1, 2022 79.3k views

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Chris Wingler · Answer 1 · 2022-04-06T05:01:57+0000

R = # of Gladiolus Mrs. Rouse has
L = # of gladiolus Mrs. Leal has

R = 3L
R+L = 128

Solution for number of Gladiolus each has

3L + L = 128

4L = 128

L = 32

R = 3(32) = 96

Mrs. Rouse has three times as many gladiolus as Mrs. Leal together they have 128 gladiolus write the system of equations for this situation ?

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