Determine the equations of the asymptotes: g(x)= (2x^2+1)/(x+3)

Question

Determine the equations of the asymptotes: g(x)=
`(2x^2+1)/(x+3)`

Answer 1

• x = -3
• y = 2x -6

Explanation:

The vertical asymptote is found where the denominator is zero, at x = -3.

The slant asymptote is the quotient of the division: 2x -6.

g(x) = (2x^2+1)/(x +3)

g(x) = 2x -6 +19/(x+3)