Question

An adiabatic nozzle has an inlet area of 1 m^2 and an outlet area of 0.25 m^2. Water enters the nozzle at a rate of 5 m^3/s and a pressure of 150 kPa. What is the velocity at the exit? What is the pressure?

Answer 1

v=20m/S

p=-37.5kPa

Step-by-step explanation:

Hello! This exercise should be resolved in the next two steps

1. Using the continuity equation that indicates that the flow entering the nozzle must be the same as the output, remember that the flow equation consists in multiplying the area by the speed

Q=VA

for he exitt

Q=flow=5m^3/s

A=area=0.25m^2

V=Speed

solving for V

`V=(Q)/(A) \\V=(5)/(0.25) =20m/s`

velocity at the exit=20m/s

for entry

`V=(5)/(1) =5m/s`

2.

To find the pressure we use the Bernoulli equation that states that the flow energy is conserved.

`(P1)/(\alpha ) +(v1^2)/(2g) =\frac{P2} {\alpha } +(v2^2)/(2g)`

where

P=presure

α=9.810KN/m^3 specific weight for water

V=speed

g=gravity

solving for P1

`((p1)/(\alpha ) +(V1^2-V2^2)/(2g))\alpha  =p2\\((150)/(9.81 ) +(5^2-20^2)/(2(9.81)))9.81  =p2\\P2=-37.5kPa`

the pressure at exit is -37.5kPa