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A world record was set for the men’s 100-m dash in the 2008 Olympic Games in Beijing by Usain Bolt of Jamaica. Bolt "coasted" across the finish line with a time of 9.69 s. If we assume that Bolt accelerated for 3.00 s to reach his maximum speed, and maintained that speed for the rest of the race, calculate his maximum speed and his acceleration. (a) In your notebook, draw a sketch of the run. The 100 m-dash is made up of what two motions? Label the sketch with vectors for velocity and acceleration at the start and finish and at the end of each motion.

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Answer:


a = 4.07 m/s^2

now his maximum speed is given as


v = 3a = 12.21 m/s

Step-by-step explanation:

Total time for which Usain Bolt accelerated is given as


t_1 = 3 s

now the velocity after uniform acceleration is given as


v_1 = 0 + 3a

now remaining time for which he run for the finish line is given as


t_2 = (9.69 - 3) = 6.69 s

now the distance moved by him during uniform acceleration is given as


d_1 = (1)/(2)a(3^2)


d_1 = 4.5 a

another distance that he moved for uniform speed is given as


d_2 = (3a)(6.69)


d_2 = 20.07 a

now total distance moved by him is 100 m so we have


20.07 a + 4.5 a = 100


a = 4.07 m/s^2

now his maximum speed is given as


v = 3a = 12.21 m/s

A world record was set for the men’s 100-m dash in the 2008 Olympic Games in Beijing-example-1