Question

_____ 10. How many milligrams of active ingredient are required to prepare 10 mL of 0.3% (w/v) solution?

Answer 1

30 mg of active ingredient is required to prepare a 0.3% (W/V) solution.

Explanation:

0.3% (w/v) solution can also be expressed as: 0.3 g active ingredient for 100 ml of solution.

So:

`(0.3g)/(100 ml) *(1000mg)/(1g)*10ml`= 30 mg

In conclusion, we need to weigh 30 mg of active ingredient and then dilute it in 10 ml of water.