Question

After an object moves for 15.0 s, it's x displacement is 27.5 m. After moving for a total of 35.0 s, the x displacement of the same object is 42.5 m. What is the average velocity of an object in the X direction during the period of time between 15.0 and 35.0

Answer 1

Average velocity
`v_(p) = 1.515 (m)/(s)`

Explanation:

The information during the motion

`t_(1)=15 s`

`t_(2)=35 s`

`x_(1)=27.5 m`

`x_(2)=42.5 m`

So the velocity in each motion is:

`v_(1)=(x_(1) )/(t_(1))\\ v_(1)=(27.5m )/(15 s)\\v_(1)=1.83 (m)/(s) \\`

`v_(2)=(x_(2) )/(t_(2))\\ v_(2)=(42.5 m )/(35 s)\\v_(1)=1.2 (m)/(s) \\`

Velocity average:

`v_(p)=(v_(1)+v_(2))/(2) = (1.83(m)/(s)+ 1.2(m)/(s))/(2)  \\v_(p)= (3.03((m)/(s) ))/(2) \\v_(p)= 1.515 (m)/(s)`