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How many grams of drug A should be used to prepare 100 mL of a 1:1250 solution?

1 Answer

4 votes

Answer:

It should be used 0.08 g of drug A to prepare 100 mL of a 1:1250 solution.

Explanation:

1:1250 solution can also be expressed as: 1 g A/ 1250 ml solution=0.08% W/V

Hence:


(0.08g(A))/(100ml(solution))*100ml(solution)= 0.08 g (A)

In conclusion, we have to weigh 0.08 g of drug A and dilute until getting 100 ml of solution.

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User Miroslav Franc
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