Question

A horizontal poly crystalline solar panel module has to be investigated by natural cooling. For crystal silicon, the thermal coefficient approximately 0.0045/K is used. Investigate the effect of air velocity on the cooling performance of PV panels at 0-5 m/s air velocities, 25-40 ºC ambient temperatures, and 400-1000 W/ m2 solar radiation

Answer 1

It is given that :

Thermal coefficient = 0.0045/K

Ambient temperature,
`$T_a = 25 - 40^\circ$`

air velocity, v = 0-5 m/s

Solar radiation,
`$G= 400-100 \ W/m^2$`

`$P=50 \ W$`

Model calculations :

Cell temperature (
`$T_c$`)

`$T_c = T_a + \left((0.25)/(5.7+3.8 \ v_w)\right) G$`

where
`$ v_w - v_a = $` wind speed / air speed

∴
`$T_c = 2 \pi + \left((0.25)/(5.7+3.8 * 1)\right) * 400$`

`$T_c = 35.526 ^\circ$`

`$\Delta T = T_c -25$`

= 35.526 - 25

= 10.526 K

Thermal coefficient = 0.0045 x 10.526

= 0.04737

Pv power =
`$(1 -C_T) * P * (G)/(1000)$`

`$=(1 -0.04737) * 50 * (400)/(1000)$`

= 17.0526 W