Question

A 12,000 kg railroad car is traveling at 2 m/s when it strikes another 10,000 kg railroad car that is at rest. If the cars lock together, what is the final speed of the two

Answer 1

The final speed of the railroad car

V= 1.14
`(m)/(s)`

Step-by-step explanation:

`v_(1)=2.1(m)/(s) \\m_(1)=12000kg\\v_(2)=0(m)/(s) \\m_(2)=10000kg \\v_(t)=?`

`m_(1)*v_(1)+m_(2)*v_(2)= (m_(1)+m_(2))*v_(t)\\v_(t)=(m_(1)*v_(1))/((m_(1)+m_(2))) \\v_(t)=(12000kg*2.1(m)/(s) )/((12000+10000)kg) \\v_(t)=1.14 (m)/(s)`

That's the final speed of the both railroad car