Question

What weight of Tris-HCL (MW=121) is required to prepare 2L of a 15% w/v solution?

Answer 1

Step-by-step explanation:

Percentage w/v means that weight of solute present in 100 ml of a solution. Hence, 15% w/v means that 15 gram of solute per 100 ml of solution.

Hence, for 2 L (or 2000 mL) preparation the amount of mass will be calculated as follows.

`(15 g)/(100 ml) * 2000 ml`

= 300 g

Thus, we can conclude that weight of Tris-HCL required is 300 g.