Question

Find the area of a triangle with sides a=5, b=8 and c=11

Answer 1

440

Explanation:

5x8=40

40x11=440

Have a good day :P :P

Answer 2

The area of the triangle with sides a=5, b=8 and c=11 is
`4 √(21) \text { square units. }`

SOLUTION:

Given, a = 5, b = 8, c = 11.

We need to find the area of the triangle with sides as given.

Let us find the area of triangle using heron’s formula:

`\begin{array}{l}{\text { Area }=\sqrt[2]{s(s-a)(s-b)(s-c)}} \\\\ {\text { Where } s=(a+b+c)/(2)}\end{array}`

Now, let us calculate value of s and put it in heron’s formula.

`s=(5+8+11)/(2)=(24)/(2)=12`

Substitute s value in heron’s formula along with a, b, c values.

`\begin{array}{l}{\text { Area }=√(12(12-5)(12-8)(12-11))} \\ {=√(12(7)(4)(1))} \\ {=\sqrt{4^(2) * 3 * 7}=4 √(21) \text { sq units. }}\end{array}`

Thus the area of the triangle with sides a=5, b=8 and c=11 is
`4 √(21) \text { square units. }`