Question

(7^2)^x=1 solve for x

Answer 1

The value of x in the given equation is 0.

Solution:

We know that any number with power 0 is 1
`(a^(0)=1)`

As given,

`\left(7^(2)\right)^(x)=1`

As per the formula,
`(a^(m))^n = a^(m+n)`

Here a is 7; 2 is m and x is n.

On substituting the values,

`(7)^(2* x)=1`

`(7)^(2* x)=7^(0)` (//any power of 0 is 1)

Hence from both the side we get,

`(2* x) = 0`

So, x = 0.

Answer 2

x=0

Explanation:

You are asked what is the number to be use as the exponent of
`7^(2)`, in order to get as answer "1".

Use the property of exponents that sates that :
`a^0=1`

In your case
`a=7^2=49` so the exponent "x"must be = 0 (zero)