Question

If 32.146g of MgSO4 is added to enough water to make 100.00mL solution, what is the molarity of MgSOA?1) 2.6706 M 2) 3.7445M 3) 0.037445 4) 0.0026706 M 5) 3869.4 M

Answer 1

`M=2.6706M`

Step-by-step explanation:

Hello,

At first, the moles of magnesium sulfate must be computed by knowing that its molecular mass has a value of 120.366 g/mol:

`n_(MgSO_4)=32.146gMgSO_4*(1mol MgSO_4)/(120.366gMgSO_4) =0.26706mol MgSO_4`

Now, by knowing that the volume must be in L, it turns out into 0.10000 L, thus:

`M=(0.26706mol MgSO_4)/(0.10000L)\\ M=2.6706M`

Best regards.