asked 66.2k views
4 votes
The rectangle below has an area of 8x^5+12x^3+20x^28x 5 +12x 3 +20x 2 8, x, start superscript, 5, end superscript, plus, 12, x, start superscript, 3, end superscript, plus, 20, x, start superscript, 2, end superscript. The width of the rectangle is equal to the greatest common monomial factor of 8x^58x 5 8, x, start superscript, 5, end superscript, 12x^312x 3 12, x, start superscript, 3, end superscript, and 20x^220x 2 20, x, start superscript, 2, end superscript. What is the length and width of the rectangle? \text{Width} = Width=W, i, d, t, h, equals \text{Length} = Length=L, e, n, g, t, h, equals

1 Answer

1 vote

Answer:

The width is:
4x^(2)

The length is:
2x^(3) +3x+5

answered
User Ejohnson
by
7.7k points
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