Question

Identify the missing coefficient in the balanced equation and classify the type of reaction.

CasN2 + 6H20 _Ca(OH)2 + 2NH3
4: Single Displacement
3. Single Displacement
4: Double Displacement
3; Double Displacement

Answer 1

3: double displacement

Answer 2

3; Double Displacement

Step-by-step explanation:

Balancing is making the number of atoms of each element same on both the sides (reactant and product side).

To find the number of atoms of each element we multiply coefficient and the subscript

For example
`5Ca_1Cl_2` contains

5 × 1 = 5 ,Ca atoms and

5 × 2 = 10, Cl atoms

If there is a bracket in the chemical formula

For example
`3Ca_3 (P_1 O_4 )_2` we multiply coefficient × subscript × number outside the bracket to find the number of atoms

(Please note: 3 is the coefficient, and if there is no number given then 1 will be the coefficient )

So

3 × 3 = 9 , Ca atoms

3 × 1 × 2 = 6, P atoms

3 × 4 × 2 = 24, O atoms are present

Let us balance the equation given

`Ca_3 N_2+6H_2 0>Ca(OH)_2+2NH_3`

(UNBALANCED)

Reactant side Number of atoms or groups Product side

of each element

3 Ca 1

2 N 2

12 H 8

6 O 2

Multiplying
`Ca(OH)_2` on the right side by 3, we will have

`Ca_3 N_2+6H_2 0>3Ca(OH)_2+2NH_3`

Reactant side Number of atoms or groups Product side

of each element

3 Ca 3

2 N 2

12 H 12

6 O 6

Balanced!!!!