Question

The perimeter of a rectangle is 200 meters. If the width is 25% of the length, find the dimensions of the rectangle

Answer 1

The rectangle dimensions are 20 m by 80 m

Explanation:

Let W represent the width and L the length. Then W = 0.25L.

The perimeter, P, is 200 m. The formula for that is P = 2W + 2L.

Substituting 0.25L for W, we get:

2(0.25L) + 2L = 200 m, or (after mult. both sides by 2): L + 4L = 400 m

Then 5L = 400 m, and L = 80 m. Thus, W = 0.25(80 m) = 20 m.

The rectangle dimensions are 20 m by 80 m