Question

20 points!! I need help

A rectangular pool is surrounded by a walk 3 meters wide. The pool is 5 meters longer than its width. If the total area of the pool and walk is 387 square meters more than the area of the​ pool, find the dimensions of the pool.

Answer 1

11.33 * 16.33 meters to the nearest hundredth.

Explanation:

Let the width of the pool be x meters, then the length is x+5 meters.

The length of whole area = x + 5 + 2(3) = x + 11 meters and the width is

x + 2(3) = x + 6 meters.

So we have the equation (x + 6)(x + 11) = 387.

x^2 + 17x + 66 = 387

x^2 + 17x - 321 = 0

x = [-17 +/- sqrt (17^2 - 4*1*-321)] / 2

x = 11.33 meters

So the width is 11.3 m and the length is 16.33 meters.