Question

HELP!

What is the solution of the equation when solved over the complex numbers?

Answer 1

`±2i√(6) = x`

Explanation:

`0 = {x}^(2) + 24 \\ \\ -24 = {x}^(2) \\ \\ √([4][6][i]) = \sqrt{{x}^(2)} \\ \\ ±2i√(6) = x`

The square root of something is ALWAYS negative and positive.

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