Answer:
a=-3
Explanation:
find the equation of the line parallel to the line x−3y=3 passing through the point (6,−1).
The equation of the line in the slope-intercept form is y=x3−1.
The slope of the parallel line is the same: m=13.
So, the equation of the parallel line is y=x3+a.
To find a, we use the fact that the line should pass through the given point: −1=(13)⋅(6)+a.
Thus, a=−3.