Question

Calculate the density of the FCC nickel lattice with an interstitial hydrogen in the centered position of the unit cell. You may assume that there is no lattice dilation due to the presence of the hydrogen atom. a=3.524A, At.Wt. = 58.7g/mole,

Answer 1

`\rho=8907.94\ Kg/m^3`

Step-by-step explanation:

Given that

a=3.524 A

At.Wt. ,M= 58.7 g/mole,

For FCC

Z = 4

`4r=\sqrt2\ a`

The density given as

`\rho=(ZM)/(N_Aa^3)`

`\rho=(4* 58.7* 10^(-3) )/( 6.023* 10^(23)* (3.524* 10^(-10))^3)`

`\rho=8907.94\ Kg/m^3`

So the density is
`\rho=8907.94\ Kg/m^3`