Question

Determine linear atomic density along 11011 direction of a FCC unit cell with a constant a (cube edge length).

Answer 1

`LD=(1)/(\sqrt2 \ a)`

Step-by-step explanation:

Given that

Unit cell is in FCC

Here given direction is not clear visible so we take direction [101].

We know that linear density(LD) given as

`LD=(Number\ of\ atoms\ in\ the\ direction\ vector)/(d_([101]))`

So the number of atom will be 1 in direction [101]

In FCC

`a=2\sqrt2 \ r`

`LD=(1)/(\sqrt2 \ a)`

`LD=(1)/(4r)`