Question

A 854 kg car is traveling at 18.1 m/s. The driver wishes to go faster, so he pushes down on the gas pedal, and a force of 1260 N acts on the car to speed it up. After 4.1 s, how many meters per second will the car be traveling at? Round your answer to the nearest tenth.

Answer 1

The car will be traveling at 24.2 m\s.

Step-by-step explanation:

The first relationship we can estabilish between the measures is:

`F = ma`

In which F, in N, is the force, m in kg is the mass and a is the accelation.

In this problem, we have that:

`F = 1260, m = 854`

So

`F = ma`

`1260 = 854a`

`a = (1260)/(854)`

`a = 1.48`

We also can relate the speed to the accelaration, by the following formula:

`v = v_(0) + at`

In which v is the speed,
`v_(0)` is the initial speed, a is the acceleration and t is the time.

We have that,
`v_(0) = 18.1, a = 1.48, t = 4.1`

So:

`v = v_(0) + at`

`v = 18.1 + 1.48*4.1`

`v = 24.2 m\s`

The car will be traveling at 24.2 m\s.