Question

What is the slope intercept form for this equation?y-3=6(x+2)

Answer 1

`\bf y-3=6(x+2)~\hfill \begin{array} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ \stackrel{slope}{y-y_1=\stackrel{\downarrow }{m}(x-x_1)} \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{3}=\stackrel{\stackrel{m}{\downarrow }}{6}[x-\stackrel{x_1}{(-2)}]`