Through point (0, 10) and PERPENDICULAR to the line through (-2, -9) and (-4, -17)?

Question

asked Sep 28, 2020 217k views

1 Answer

Rfunduk · Answer 1 · 2020-10-02T23:52:59+0000

Compute the slope of the line through (-2, -9) and (-4, -17):

$(-9-(-17))/(-2-(-4))=\frac82=4$

Any line perpendicular to this line will have slope -1/4. The one that passes through (0, 10) satisifes

$y-10=-\frac14(x-0)\implies\boxed{y=10-\frac x4}$