Question

A bird watcher spots a sparrow in a tree. The sparrow sits in a nest that is 10.5 feet above the bird watcher's eye level, at a 35° angle of elevation from the bird watcher. The bird watcher then notices a hawk in the same tree, 7.4 feet above the sparrow, at a certain angle of elevation. The bird watcher stands 15 feet from the base of the tree. What is the angle of elevation from the bird watcher to the hawk?

Answer 1

the angle is 50 degrees.

Step-by-step explanation:

To solve this trigonometric problem we need ot remember that:

`\alpha=arctg((O)/(A))`

where O is the opposite side of the triangle and A the adjacent

The hawk is 7.4 feet above the sparrow so:

`O=10.5+7.4\\O=17.9ft`

`\alpha =arctg((17.9)/(15))=50^o`