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Find the y-intercept of f(x)=3x^2 -2x-8

asked
User Jaybee
by
8.4k points

2 Answers

6 votes

Answer:

-8

Explanation:

y-intercept of f(x)=3x^2 -2x-8 when : x =0

f(0) = 3(0)² -2(0) -8 = - 8

answered
User Tosi
by
7.6k points
4 votes

Answer:

The y-intercept of y = f(x) =
3x^2-2x-8 is -8.

Solution:

From question, given equation is f(x) =
3 x^(2)-2 x-8

We have to find the y-intercept of the above equation

The y-intercept of the graph is the point where the function crosses the y-axis. The x-value is equal to zero for every point on the y-axis.

From question given that


y=f(x)=3 x^(2)-2 x-8 --- eqn 1

On substituting x = 0 in equation (1), the above equation becomes


y=3(0)^(2)-2(0)-8

On simplifying, we get

y = 0-0-8

y = -8

So the y-intercept of f(x) =
3 x^(2)-2 x-8 \text { is }-8

answered
User Miroslav Prymek
by
8.3k points

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