Question

Water at 4.4°C is to flow through a horizontal, commercial steel pipe having a length of 305 m at the rate of 150 gal/min. If a head of water of 6.1 m is available to overcome the friction loss F, calculate the pipe diameter.

Answer 1

d = 70.5 mm

Step-by-step explanation:

given,

length of pipe = 305 m

discharge rate = 150 gal/min

pipe diameter = ?

1 gal/min = 6.30902 × 10⁻⁵ m³/s

150 gal/min = 150 × 6.30902 × 10⁻⁵ m³/s

= 9.46 × 10⁻³ m³/s

`h = (flv^2)/(2gd)`

`h = (flv^2)/(2gd)`

Q = A V

`h = (fl((Q)/(A))^2)/(2gd)`

`h = (fl((Q)/((\pi)/(4)d^2))^2)/(2gd)`

`h= (8flQ^2)/(\pi^2gd^5)`

f = 0.048 from moody chart using P/D = 0.00015

`(1)/(d^5)= (6.1* \pi^2* 9.8)/(8* 0.048* 305* 0.00946^2)`

d = 70.5 mm

Diameter of the pipe is equal to 70.5 mm