A 0.40-μF capacitor is connected to a 5.0-V battery. How much charge is on each plate of the capacitor? Express your answer using two significant figures.

Question

asked Nov 28, 2020 199k views

1 Answer

Gerald Ferreira · Answer 1 · 2020-12-04T21:33:33+0000

Answer:

Q=2.0*10^(-6)C

Step-by-step explanation:

The equation of charge on the capacitor given its capacitance and a voltage applied to it is Q=CV.

Our capacitance is expressed in microfarads, where micro stands for
*10^(-6) , so in S.I. we sill have:

Q=CV=(0.4*10^(-6)F)(5V)=0.000002C=2.0*10^(-6)C

Where the results has been expresed with two significant figures.