Question

A parallel-plate capacitor in air has a plate separation d = 4 mm and square plates with area A = 25.0 cm^2. The plates are maintained to a constant potential difference of 255 V. Determine the charge on the plates and the energy stored by the capacitor.

Answer 1

Answer:
`179.79 * 10^(-9) J`

Step-by-step explanation:

Given

Separation (d)=4 mm

Area of cross-section
`=25 cm^2`

Potential difference=255 V

`C=(\epsilon A)/(d)=5.53 * 10^(-12)F`

charge
`(Q)=CV=5.53* 225=1411.10* 10^(-12) C`

Energy stored
`=(cv^2)/(2)`

`E=(5.53* 10^(-12) 255^2)/(2)=179.79 * 10^(-9) J`