Question

Multiply (2x^2-3x)(3x^2+2x-1)

Answer 1

Step-by-step explanation: -9X3+12x2-x-2

Answer 2

Multiplication of
`\left(2 x^(2)-3 x\right) \text { and }\left(3 x^(2)+2 x-1\right) \text { is } 6 x^(4)-5 x^(3)-8 x^(2)+3 x`

SOLUTION:

We need to multiply
`\left(2 x^(2)-3 x\right) \text { and }\left(3 x^(2)+2 x-1\right)`

`=\left(2 x^(2)-3 x\right)\left(3 x^(2)+2 x-1\right)`

`=2 x^(2)\left(3 x^(2)+2 x-1\right)-3 x\left(3 x^(2)+2 x-1\right)`

`=\left(2 x^(2) * 3 x^(2)\right)+\left(2 x^(2) * 2 x\right)+\left(2 x^(2) *(-1)\right)-\left(3 x * 3 x^(2)\right)-(3 x * 2 x)-(3 x *(-1))`

`=6 x^(4)+4 x^(3)-2 x^(2)-9 x^(3)-6 x^(2)+3 x`

`=6 x^(4)+(4-9) x^(3)-(2+6) x^(2)+3 x`

`=6 x^(4)-5 x^(3)-8 x^(2)+3 x`

Hence, multiplication of
`\left(2 x^(2)-3 x\right) \text { and }\left(3 x^(2)+2 x-1\right) \text { is } 6 x^(4)-5 x^(3)-8 x^(2)+3 x`