asked 129k views
4 votes
hi everybody please who could help me with this question, i am stuck here.. the question is ( solve for x in this equation ( 2sin^2 x - sinx))​

asked
User Dhke
by
8.4k points

1 Answer

3 votes

Answer:

Explanation:

2sin² x - sinx=0

sinx(2sinx - 1 ) = 0

sinx = 0 or 2sinx - 1 = 0

sinx=0 or sinx = 1/2

continue solve in : IR or [0, 2π] ?????

answered
User VanSkalen
by
8.7k points

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