asked 12.0k views
5 votes
A 85.4 kg ice skater is moving at 5.97 m/s when she grabs the loose end of a rope, the opposite end of which is tied to a pole. She then moves in a circle of radius 0.895 m around the pole. Find the force exerted by the rope on her arms. The acceleration of gravity is 9.8 m/s 2 . Answer in units of kN.

asked
User Amari
by
8.8k points

1 Answer

3 votes

Answer:


F_c=35.81kN

Step-by-step explanation:

When the ice skater grabs the loose end of the rope, he experiences a centipretal force, where the speed he had before grabbing the rope is the tangential speed, this force is given by:


F_c=ma_c\\F_c=m((v_T)^2)/(r)\\F_c=85.4kg((5.97(m)/(s))^2)/(0.085m)\\F_c=35.81kN

answered
User Asil
by
8.1k points
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