Question

Joyce had some money. She bought a dress, a shirt and a watch. She spent 1/5 of her money on a shirt. The shirt cost $24 less than a dress. The watch cost $102. She was left with 1/4 of the amount of money she had at first. How much money did Joyce have at first?

Help me please!

Answer 1

How much money did Joyce have at first? = x

The shirt = s

The dress = d

The watch = w

s = x / 5 +

d =s+24 -----> d = x/5 +24

w = 102

-------------------

s + d +w = x / 5 + x / 5 + 24 + 102

s + d +w = 2x / 5 + 126

She was left with 1/4 of the amount of money she had at first: x - (s + d +w) = x/4

x - (s + d +w) = x/4

x - (2x / 5 + 126) = x/4

x - 2x / 5 - 126 = x/4

x - 2x / 5 - x/4 = 126

x(1- 2/5 -1/4) = 126

x(7/20) = 126

x = 126(20/7)

Ans. x=360