Question

The place kicker on a football team kicks a ball from ground level with an initial speed of 4.00 m/s at an angle of 29.0° above the horizontal. How long is the ball in the air, in seconds, before it lands on the ground again? You may neglect air resistance.

Answer 1

0.4 s

Step-by-step explanation:

The time that the ball is in the air can be found with the next formula:

`time = t = (2v_(o)sen\beta)/(g)`

where
`v_(o)` is the initial velocity of the ball, in this case:

`v_(o)=4.00 m/s`

β is the angle: β = 29.0°

And g is the acceleration of gravity:
`g=9.81m/s^2`

Replacing all the values to find t, we have:

`time = t = (2(4m/s)sen(29))/(9.81m/s^2) = 0.4s`

Thus, the ball is 0.4s in the air.