Question

What is the equation of the graph below?

y = sin(x/3) y=sin(3x) y =sin(0.3x) y = sin(2x/3)


photomath doesn't have this to find the answer this is precalculous so 5th graders don't answer this question you will surely get this wrong or even 9th graders unless you skipped 3 grades above normal 9th grade math

Answer 1

y = sin 3x.

Explanation:

We see from the graph that y = sin 2π/3 = 0.

Let x = 2π/3 , then substituting in y = sin 3x we get

y = sin 3 * (2π/3) = sin 2π = 0.

Answer 2

Option B is the correct answer.

Explanation:

From the graph we can see that

`y\left ( (2\pi)/(3)\right )=0`

Substituting in all the options given,

Option A

`y=sin\left ( (x)/(3)\right )\\\\y\left ( (2\pi)/(3)\right )=sin\left ( ((2\pi)/(3))/(3)\right )\\\\y\left ( (2\pi)/(3)\right )=sin\left ( (2\pi)/(9)\right )=0.643\\\\y\left ( (2\pi)/(3)\right )=0.643\\eq 0`

Option A is not correct.

Option B

`y=sin3x\\\\y\left ( (2\pi)/(3)\right )=sin\left (3* (2\pi)/(3) \right )\\\\y\left ( (2\pi)/(3)\right )=sin2\pi=0\\\\y\left ( (2\pi)/(3)\right )=0=0`

Option B is correct.

Option C

`y=sin0.3x\\\\y\left ( (2\pi)/(3)\right )=sin\left (0.3* (2\pi)/(3) \right )\\\\y\left ( (2\pi)/(3)\right )=sin0.2\pi=0\\\\y\left ( (2\pi)/(3)\right )=0.588\\eq 0`

Option C is not correct.

Option D

`y=sin\left ( (2x)/(3)\right )\\\\y\left ( (2\pi)/(3)\right )=sin\left ( ((2* 2\pi)/(3))/(3)\right )\\\\y\left ( (2\pi)/(3)\right )=sin\left ( (4\pi)/(9)\right )=0.985\\\\y\left ( (2\pi)/(3)\right )=0.985\\eq 0`

Option D is not correct.

Option B is the correct answer.