Question

What volume in liters of 9.00×10^−2 M KH2AsO4 contains 1.90 g KH2AsO4?

Answer 1

The answer to your question is: Volume = 0.117 l

Step-by-step explanation:

Data

V = ?

M = 9 x 10 ⁻²

mass = 1,9 g of KH₂AsO₄

MW KH₂AsO₄ = 39 + 2 + 75 + 64 = 180 g

Process

180 g of KH₂AsO₄ ------------------ 1 mol

1.9 g ------------------ x

x = 0.0011 mol of KH₂AsO₄

Molarity = # of moles / volume

Volume = # of moles / molarity

Volume = 0.0011 mol of KH₂AsO₄ / 0.09

Volume = 0.117 l = 117 ml