Question

How many moles of air are there in a 3 L container at 1 atm pressure and 293
K? Use PV = nRT.

Answer 1

Moles of air 0.1245 mol.

Step-by-step explanation:

Given data:

Pressure = 1 atm

Temperature = 293 K

Volume = 3 L

Number of moles = ?

Solution:

PV = nRT

R = general gas constant = 0.0821 dm³ atm . K⁻¹ . mol⁻¹

Now we will put the values in equation

PV = nRT

n = PV / RT

n = 1 atm . 3 L / 0.0821 dm³ atm . K⁻¹ . mol⁻¹ . 293 K

n = 3 / 24.1 dm³ atm. mol⁻¹

n = 0.1245 mol