How many moles of nitrogen atoms are there present in 28 grams of Nitrogen gas

Question

asked May 16, 2020 200k views

1 Answer

Tshiono · Answer 1 · 2020-05-20T12:11:54+0000

Answer:2 × 6.022 × 10²³ atoms.

Explanation:It's 1 mole = mass of the nitrogen

Here we can say, mass of the nitrogen=1mole

1mole=6.022×10^23

And we can get the mass of nitrogen by

Mass of nitrogen=no. Of protons+neutrons

Mass of nitrogen=7+7

Mass of nitrogen=14u

So we get that,

Mass of the nitrogen=1mole

Then,

14g=1mole

28g=xmole

14:28::1:x

14x=28

X=2

So,

28g=2moles