Question

The density of pure gold is 19.3g/cm3. What is the volume of 1.00 g of pure gold?

Answer 1

Answer: Volume of 1g of pure gold
`v=0.05181 \mathrm{cm}^(3)`

Given;

Density of a pure gold=19.3
`g / c m^(3)`

Mass of a pure gold =1g

To find:

Volume of 1g of pure gold

Solution:

According to the formula,

Density= Mass/Volume

`\rho=m / v`

Where
`\rho`=density of pure gold

m=mass of pure gold

v=volume of pure gold

From the above equation volume can be calculated as

`v=m / \rho`

Substitute the values of mass and density value in the above equation

`v=1 / 19.3`

`v=0.05181 \mathrm{cm}^(3)`

Result:

Thus the volume of 1g of pure gold is
`v=0.05181 \mathrm{cm}^(3)`