Question

A 16 kg mass suspended from a light spring is replaced by a 4 kg mass. What factor changes the frequency of the oscillation? (a) 1/4

(b) 2.0
(c) 4.0
(d) 1/2
(e) does not change

Answer 1

Frequency change by a factor of 2.

(b) is correct option.

Step-by-step explanation:

Given that,

Mass = 16 kg

Replaced mass = 4 kg

We need to calculate the frequency

Using formula of frequency

`f=(1)/(2\pi)\sqrt{(k)/(m)}`

Put the value into the formula

`f_(1)=(1)/(2\pi)\sqrt{(k)/(16)}`

`f_(1)=(1)/(2\pi)(√(k))/(4)}`....(I)

`f_(2)=(1)/(2\pi)\sqrt{(k)/(4)}`

`f_(2)=(1)/(2\pi)(√(k))/(2)}`...(II)

`f_(2)=2f_(1)`

Hence, Frequency change by a factor of 2.