Question

Write an equation in point slope form for the line that passes through (3,0) and (-3,-6).

Answer 1

Explanation:

The point-slpe form of an equation of a line:

`y-y_1=m(x-x_1)`

m - slope

(x₁, y₁) - point on a line

The formula of a slope:

`m=(y_2-y_1)/(x_2-x_1)`

(x₁, y₁), (x₂, y₂) - points on a line

We have the points (3, 0) and (-3, -6).

Calculate the slope:

`m=(-6-0)/(-3-3)=(-6)/(-6)=1`

Put the value of the slope and the coordinates of the point (3, 0) or (03, 06) to the equation of a line:

FOR (3, 0):

`y-0=1(x-3)\to y=1(x-3)\to y=x-3`

FOR (-3, -6):

`y-(-6)=1(x-(-3))\to y+6=1(x+3)\to y+6=x+3`